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a^2=20.25
We move all terms to the left:
a^2-(20.25)=0
We add all the numbers together, and all the variables
a^2-20.25=0
a = 1; b = 0; c = -20.25;
Δ = b2-4ac
Δ = 02-4·1·(-20.25)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-9}{2*1}=\frac{-9}{2} =-4+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+9}{2*1}=\frac{9}{2} =4+1/2 $
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